3^x^2-x+12=9^9-x

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Solution for 3^x^2-x+12=9^9-x equation: 



3^x^2-x+12=9^9-x

We move all terms to the left:

3^x^2-x+12-(9^9-x)=0

We add all the numbers together, and all the variables

-1x+3^x^2-(9^9-x)+12=0

We get rid of parentheses

-1x+3^x^2+x+12-9^9=0

We add all the numbers together, and all the variables

3^x^2-387420477=0

We move all terms containing x to the left, all other terms to the right

3^x^2=387420477

x=387420477/1

x=387420477

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